5y^2+50y+80=0

Solution for 5y^2+50y+80=0 equation:

5y^2+50y+80=0

a = 5; b = 50; c = +80;
Δ = b2-4ac
Δ = 502-4·5·80
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-30}{2*5}=\frac{-80}{10}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+30}{2*5}=\frac{-20}{10}
=-2
$